A) \[\frac{AC}{3}\]
B) \[\frac{2AC}{3}\]
C) \[\frac{AC}{2}\]
D) None of the above
Correct Answer: B
Solution :
Draw line segment DG parallel to BF. Then, In \[\Delta \,ADG,\text{ }EF||DG\] and \[AE=ED\text{ }\,\,\therefore \text{ }AF=GF\] .....(i) Similarly, in \[\Delta BCF,\text{ }DG||BF\] and \[BD=DC\text{ }\therefore \text{ }FG=GC\] .....(ii) From Eqs. (i) and (ii), CF \[\]You need to login to perform this action.
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