A) \[43\text{ }m\]
B) \[52.2\text{ }m\]
C) \[67.2\text{ }m\]
D) \[70\text{ }m\]
Correct Answer: C
Solution :
Third side of triangle \[=240-78-50=112\text{ }cm\] semi-perimeter \[\left( s \right)=\frac{240}{2}=120\] By Herons formula Area of triangle \[=\sqrt{s(s-a)\,(s-b)\,(s-c)}\] \[=\sqrt{120(120-112)(120-78)(120-50)}\] \[=1680\,{{m}^{2}}\] Now, \[\frac{1}{2}\times 50\,m\times perpendicular=Area\,of\,Triangle\] \[=\frac{1}{2}\times 50\times p=1680\Rightarrow p=\]You need to login to perform this action.
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