A) 1
B) 2
C) 4
D) None of the above
Correct Answer: D
Solution :
\[d\left( n \right)\] = no of positive divisors of n. Now \[d\left( d\left( d\left( 12 \right) \right) \right)\] No. of divisors of \[12={{2}^{2+1}}\times {{3}^{1+1}}\] \[=3\times 2=6\] \[\therefore \,\,\,\,d(d(6))\] No. of divisors of \[6={{2}^{1+1}}\times {{3}^{1+1}}\] \[=\,\,\,\,2\times 2=4\,\,\,\therefore \,\,d(4)\] Now no. of divisors of \[4={{2}^{2+1}}=\]
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