A) \[{{H}_{2}}S{{O}_{4}}\]
B) \[CaC{{l}_{2}}\]
C) \[N{{a}_{2}}S{{O}_{4}}\]
D) \[NaCl\]
Correct Answer: D
Solution :
The Equivalent weight of Sodium Chloride is same as the molecular weight because in Sodium Chloride \[(NaCl)\] one atom of Sodium and one atom of Chlorine is in equal proportion whereas in other options molecules have different atomic composition.
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