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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-16

  • question_answer
    The length of a minute hand of a wall clock is 9 cm. What is the area swept (in \[c{{m}^{2}}\]) by the minute hand in 20 minutes? (Take \[\pi =3.14\])

    A)  \[88.78\]                      

    B)  \[84.78\]

    C)  \[67.74\]                      

    D)  \[57.78\]

    Correct Answer: B

    Solution :

    Angle made by minute hand in 20 minutes \[=\frac{360{}^\circ }{60}\times 20=120{}^\circ \] Area swept by it \[=\frac{\theta }{360{}^\circ }\pi {{r}^{2}}\] \[=\frac{120{}^\circ }{360{}^\circ }\times 3.14\times {{(9)}^{2}}=\mathbf{84}\mathbf{.78}\,{{\mathbf{m}}^{\mathbf{2}}}\]


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