A) \[4\frac{1}{2}\]
B) \[4\frac{1}{6}\]
C) \[9\frac{1}{2}\]
D) \[\frac{1}{9}\]
Correct Answer: B
Solution :
\[8\frac{1}{2}-\left[ 3\frac{1}{4}\div \left\{ 1\frac{1}{4}-\frac{1}{2}\left( 1-\frac{1}{2}-\frac{1}{3}-\frac{1}{6} \right) \right\} \right]\] \[=\frac{17}{2}-\left[ \frac{13}{4}\div \left\{ \frac{5}{4}-\frac{1}{2}\left( \frac{3}{2}-\frac{3}{6} \right) \right\} \right]\] \[=\frac{17}{2}-\left[ \frac{13}{4}\div \left\{ \frac{5}{4}-\frac{1}{2}\times 1 \right\} \right]=\frac{17}{2}-\left[ \frac{13}{4}\div \frac{3}{4} \right]\] \[=\frac{17}{2}-\frac{13}{3}=\frac{25}{6}=\mathbf{4}\frac{\mathbf{1}}{\mathbf{6}}\]
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