A) \[8\pi \]
B) \[16\sqrt{3}-8\pi \]
C) \[16\sqrt{3}-4\pi \]
D) \[16\sqrt{3}-2\pi \]
Correct Answer: B
Solution :
The area of bounded portion\[=\left( \sqrt{3}-\frac{\pi }{2} \right){{r}^{2}}=\left( \sqrt{3}-\frac{\pi }{2} \right){{4}^{2}}=\mathbf{16}\,\sqrt{\mathbf{3}}\mathbf{-8}\pi \]You need to login to perform this action.
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