A) \[120{}^\circ \]
B) \[100{}^\circ \]
C) \[80{}^\circ \]
D) \[110{}^\circ \]
Correct Answer: A
Solution :
\[\angle ACD=50{}^\circ +30{}^\circ \] \[80{}^\circ \] (Ext. angle property) \[\therefore \] In \[\Delta \,ECD\] \[\angle E+\angle C+\angle D=180{}^\circ \] \[\angle CED+\text{ }80{}^\circ +40{}^\circ =180{}^\circ \] \[\therefore \,\,\,\,\angle CED=60{}^\circ \] Now, \[\angle AED+\angle CED=180{}^\circ \] (linear pair) \[\therefore \,\,\,\,\,\,\angle AED=180{}^\circ -60{}^\circ =\]
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