A) 45 kg
B) 50 kg
C) 55 kg
D) 60 kg
Correct Answer: D
Solution :
\[1\text{ }{{m}^{3}}=480\text{ }kg\] Let the side of the square rod = a Volume of the square rod \[={{a}^{2}}\times l\] \[{{a}^{2}}\times 4m=1{{m}^{3}}\Rightarrow {{a}^{2}}=\frac{1}{4}{{m}^{2}}\Rightarrow a=\frac{1}{2}m\] \[\therefore \] Volume of solid cube \[=\,\,\,\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=\frac{1}{8}\,\,\,{{m}^{3}}\] Now, \[1{{m}^{3}}=480kg\] \[\therefore \,\,\,\,\,\frac{1}{8}\,{{m}^{3}}=\frac{480}{8}=60\,kg\] \[\therefore \] Weight of the solid cube \[=\,\,\,\mathbf{60}\,\mathbf{kg}\]
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