A) \[\sqrt{\frac{x}{y}}\]
B) \[\sqrt{x+y}\]
C) \[\sqrt{xy}\]
D) \[\frac{x}{y}\]
Correct Answer: C
Solution :
\[\alpha +\beta =90{}^\circ \] -(Given) \[\tan \alpha =\frac{h}{y}\] ??. (i) \[\tan \beta =\frac{h}{x}\,\,\,\Rightarrow \,\,\tan \,\,(90{}^\circ -\alpha )=\frac{h}{x}\] \[\cot \,\alpha =\frac{h}{x}\] ?.. (ii) From equation (i) and (ii), We get, \[1+xy={{h}^{2}}\Rightarrow h=\sqrt{\mathbf{xy}}\]You need to login to perform this action.
You will be redirected in
3 sec