A) \[{{60}^{o}}\]
B) \[{{100}^{o}}\]
C) \[{{120}^{o}}\]
D) \[{{140}^{o}}\]
Correct Answer: C
Solution :
In\[\Delta ABD\], \[AD=BD=AB=\]radius In \[\Delta ACB\], \[AC=CB=AB=\]radius \[\therefore \] \[\angle DBC={{60}^{o}}+{{60}^{o}}={{120}^{o}}\]You need to login to perform this action.
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