A) \[0\]
B) \[1\]
C) \[-1\]
D) \[2\]
Correct Answer: B
Solution :
\[x={{k}^{3}}-3{{k}^{2}}\] When\[x=y\], then \[{{k}^{3}}-3{{k}^{2}}=1-3k\] \[\Rightarrow \] \[{{k}^{3}}-3{{k}^{2}}+3k-1=0\] \[\Rightarrow \] \[{{(k-1)}^{3}}=0\Rightarrow k-1=0\] \[\Rightarrow \] \[k=1\]You need to login to perform this action.
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