A) 60 cm
B) 56 cm
C) 68 cm
D) 54 cm
Correct Answer: B
Solution :
Side of rhombus = 20 cm One of the diagonal = 24 cm [\[\because \] Rhombus diagonals a intersect each other at\[90{}^\circ \]] In \[\Delta \,DOC-\] \[{{(DC)}^{2}}={{(DO)}^{2}}+{{(CO)}^{2}}\Rightarrow 400\,\,\,144+{{(CO)}^{2}}\] \[CO=\sqrt{256}=16cm.\,\,\Rightarrow \,\,AC=2CO\] \[=2\times 16=32\,\,cm.\] The sum of both diagonals \[=32\,+24=\underline{\mathbf{56}\,\mathbf{cm}}\]You need to login to perform this action.
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