A) 1
B) 0
C) 2
D) \[-1\]
Correct Answer: C
Solution :
\[\frac{\cot \,38{}^\circ }{tan52{}^\circ }+\frac{\sin 42{}^\circ }{\cos 48{}^\circ }=\frac{\tan 52{}^\circ }{\tan 52{}^\circ }+\frac{\cos 48{}^\circ }{\cos \,48{}^\circ }\] \[\left[ \begin{align} & \cot \,\left( 90{}^\circ -\theta \right)=\tan \theta \\ & \sin (90{}^\circ -\theta )=\cos \theta \\ \end{align} \right]\] \[=\,\,\,1+1=\underline{\mathbf{2}}\]
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