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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-22

  • question_answer
    The breadth of rectangular surface is \[\frac{4}{5}\]th of its length. If the area of the surface is \[500\text{ }{{m}^{2}},\] then perimeter of surface is -

    A)  \[45\,cm\]                    

    B)  \[90\,cm\]

    C)  \[100\,cm\]                   

    D)  \[80\,cm\]

    Correct Answer: B

    Solution :

     Let the length of rectangular floor is x cm, \[\because \]  Breadth  \[=x\times \frac{4}{5}=\frac{4x}{5}\] \[\therefore \]   Area of floor \[=x\times \frac{4x}{5}=500\] \[4{{x}^{2}}=2500\Rightarrow \,\,{{x}^{2}}=625\Rightarrow x=\sqrt{625}=25\] Length of floor \[=25\text{ }cm\] Breadth of floor \[=25\times \frac{4}{5}=20\,cm.\] \[\therefore \]  Perimeter \[=2(l+b)\] \[=\,2(25+20)=\underline{\mathbf{90}\,\mathbf{cm}}\]


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