A) \[+,\times ,-,\div ,=\]
B) \[\times ,+,\div ,-,=\]
C) \[\div ,+,\times ,-,=\]
D) \[\times ,-,\div ,+,=\]
Correct Answer: B
Solution :
Solving from the choices: [A] After inserting the operators \[(+,\,\times ,-,\div ,=)\] We get, \[10+3\times 4-2\div 1=31\] [Use 'BODMAS' rule] \[10+12-2=31\Rightarrow 20\ne 31\] [B] After inserting the operators \[(\times ,+,\div ,-,=)\]. We get, \[\underline{\mathbf{10\times 3+4\div 2-1=31}}\] [Use 'BODMAS' rule] \[30+2-1=31\Rightarrow 31=31\] [C] After inserting the operators \[(\div ,\,+,\,\times ,\,-,\,=)\]. We get, \[10\div 3+4\times 2-1=31\] [Use BODMAS 'Rule] \[3.33+8-1=31\Rightarrow \,10.33\ne 31\] [D] After inserting the operators \[(\times ,\,-,\,\div ,+,=).\]. We get, \[=10\times 3-4\div 2+1=31\] [Use BODMAS 'Rule] \[30-2+1=31\Rightarrow 29\ne 31\]
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