A) \[49\,c{{m}^{2}}\]
B) \[\frac{49}{2}c{{m}^{2}}\]
C) \[\frac{49\sqrt{3}}{2}c{{m}^{2}}\]
D) \[49\sqrt{3}\,c{{m}^{2}}\]
Correct Answer: C
Solution :
Let ABCO is a rhombus whose 3 vertices A, B and C lie on circumference of circle and one vertex lies on center. \[\therefore \] \[BO=OC=AO=7\text{ }cm\] (Radius of circle) \[AB=BC=7cm\] (Sides of rhombus) \[\because \] Figure formed two equilateral triangles. \[\therefore \] Area of rhombus = 2 \[\times \] area of equilateral triangle. \[=2\,\times \frac{\sqrt{3}}{4}\times 7\times 7=\underline{\frac{\mathbf{49}\sqrt{\mathbf{3}}}{\mathbf{2}}\,\mathbf{c}{{\mathbf{m}}^{\mathbf{2}}}}\]You need to login to perform this action.
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