A) \[45{}^\circ \]
B) \[30{}^\circ \]
C) \[60{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: B
Solution :
Let AB is the height of pole and BC is the length of shadow of the pole. Then, In \[\Delta ABC,\] \[\tan \theta =\frac{AB}{BC}=\frac{51\sqrt{3}}{153}\] \[\tan \theta =\frac{\sqrt{3}}{3}=\frac{1}{\sqrt{3}}=\tan 30{}^\circ \,\,\therefore \,\,\,\theta =\underline{\mathbf{30{}^\circ }}\]You need to login to perform this action.
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