SSC
Sample Paper
SSC CHSL (10+2) Sample Test Paper-24
question_answer
The denominations of a triangle is 9 cm, 40 cm and 41 cm, then find the length of circumcircle of that triangle?
A)\[21\,cm.\]
B) \[20.5\,cm.\]
C) \[41\,cm.\]
D) \[40\,cm.\]
Correct Answer:
B
Solution :
Let ABC is a right angle triangle Here, \[AB==40cm.\,\,\,\Rightarrow BC=9cm.\] \[AC=41\text{ }cm\]. \[\therefore \] Length of radius of circumcircle \[=\,\,\,\,\frac{AC}{2}=\frac{41}{2}=\underline{\mathbf{20}\mathbf{.5}\,\mathbf{cm}\mathbf{.}}\]