SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-25

  • question_answer
    Select the correct combination of mathematical operations to replace sings and to balance the given equation. \[6*3*2*5*2*19\]

    A)  \[\times ,+,\div ,\times ,=\]                    

    B)  \[+,\times ,\div ,\times ,=\]

    C)  \[\times ,\div ,+,\times ,=\]                    

    D)  \[\times ,\times ,\div ,+,=\]

    Correct Answer: C

    Solution :

     Solving from the choices: [a] Inserting the operators \[(\times ,\,+,\,\div ,\,\times ,=)\]. We get, \[6\times 3+2\div 5=19\] [Use 'BODMAS' rule] \[18+0.8=19\Rightarrow 18.8\ne 19\] [b] Inserting the operators \[(\times ,\,+,\,\div ,\times ,=).\] We get, \[6+3\times 2-5\times 2=19\][Use 'BODMAS' rule] \[6+3\times 0.4\times 2=9\] \[6+2.4=19\Rightarrow 8.4\ne 19\] [c] Inserting the operators \[(\times ,\,+,\,\div ,\,\times ,\,=)\] We get, \[\underline{\mathbf{6\times 3\div 2+5\times 2=19}}\]| [Use 'BODMAS' rule] \[9+10=19\Rightarrow 19=19\] [d] Inserting the operators \[(\times ,\,+,\,\div ,\,\times ,\,=)\]. We get, \[6\times 3\times 2\div 5+2=19\][Use 'BODMAS' rule] \[6\times 3\times 0.4+2=19\Rightarrow 9.2\ne 19\]


You need to login to perform this action.
You will be redirected in 3 sec spinner