A) \[46{}^\circ C\]
B) \[43{}^\circ C\]
C) \[40{}^\circ C\]
D) \[49{}^\circ C\]
Correct Answer: A
Solution :
Mean temperature of Monday to Wednesday \[=\text{ }41{}^\circ C\] \[\therefore \] Total temperature of Monday to Wednesday\[=\text{ 123}{}^\circ C\] Mean temperature of Tuesday to Thursday \[=\text{ 43}{}^\circ C\] \[\therefore \] Total temperature of Tuesday to Thursday \[=\text{ 129}{}^\circ C\] So, Temperature of Thursday -Temperature of Monday \[=\text{ }129{}^\circ -123{}^\circ =6{}^\circ \] Let the temperature of Monday be \[x{}^\circ \] \[15\times \frac{x}{100}=6\,\,\Rightarrow \,\,\,x=\frac{6\times 100}{15}=40{}^\circ \] So, Temperature of Thursday \[=\,\,\,\,\,\,40+6=\underline{\mathbf{46{}^\circ }}\]
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