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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-2

  • question_answer
    In the adjoining figure \[AD,\,\,AE\] and \[BC\] are tangent to the circle at \[D,\,\,E,\,\,F\] respectively then:

    A) \[AD=AB+BC+AC\]

    B) \[2AD=AB+BC+AC\]  

    C) \[AD=\frac{1}{2}(AB+BC+AC)\]

    D) \[3AD=AB+BC+AC\]

    Correct Answer: B

    Solution :

     As the tangents drawn to a circle from a point outside It are equal, we have\[AD=AE\], \[BD=BF\]and\[CE=CF\] \[AD=AB+BD=AB+BF\] \[AD=AC+CE=AC+CF\] \[\therefore \]\[2AD=AB+AC+BF+CF\] \[2AD=AB+AC+BC\]


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