A) \[{{40}^{o}}\]
B) \[{{60}^{o}}\]
C) \[{{80}^{o}}\]
D) \[{{85}^{o}}\]
Correct Answer: B
Solution :
\[\angle OCX={{45}^{o}}\] \[\angle COD+\angle COX={{180}^{o}}\] \[\Rightarrow \]\[\angle COX={{180}^{o}}-\angle COD={{180}^{o}}-{{105}^{o}}={{75}^{o}}\] In\[\Delta OCX\] \[\angle OCX+\angle COX+\angle OXC={{180}^{o}}\] \[\Rightarrow \] \[{{45}^{o}}+{{75}^{o}}+\angle OXC={{180}^{o}}\] \[\Rightarrow \] \[\angle OXC={{180}^{o}}-{{120}^{o}}={{60}^{o}}\] \[\Rightarrow \] \[x={{60}^{o}}\]You need to login to perform this action.
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