A) \[h\cot x+h\]
B) \[h\cot x-h\]
C) \[h\tan x-h\]
D) \[h\tan x+h\]
Correct Answer: B
Solution :
\[AB=\]Building \[=h\] metre \[AD=\]Chimney\[=y\] metre From\[ABCD\], \[\tan {{45}^{o}}=\frac{BD}{BC}\] \[\Rightarrow \] \[1=\frac{h+y}{BC}\] \[\Rightarrow \] \[BC=h+y\] ? (i) From\[\Delta ABC\], \[\tan x=\frac{AB}{BC}\] \[BC=h\cot x\] ?(ii) From equations (i) and (ii). \[h+y=h\cot x\] \[\Rightarrow \] \[y=(h\cot x-h)\]metreYou need to login to perform this action.
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