A) 10
B) 13
C) 8
D) 6
Correct Answer: D
Solution :
Work of \[B\] for \[1\]day \[=\frac{1}{10}\]and work of \[C\] for \[1\] day \[=\frac{1}{15}\] Work of \[(B+C)\] for \[2\] days\[=2\left( \frac{1}{10}+\frac{1}{15} \right)=\frac{1}{3}\] \[\therefore \]Remaining work \[=1-\frac{1}{3}=\frac{2}{3}\] \[\because \]\[1\] Work is done by \[A\] in \[9\] days \[\therefore \]\[\frac{2}{3}\] work is done by \[A\] \[=9\times \frac{2}{3}=6\]daysYou need to login to perform this action.
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