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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-3

  • question_answer
    The diameter of a wheel is 98 cm. The number of revolutions in which it will have to cover a distance of 1540 m is

    A)  500                               

    B)  600

    C)  700                 

    D)         800

    Correct Answer: A

    Solution :

     Distance covered by wheel is one revolution = circumference of the wheel \[=\pi \times \text{diameter}=\frac{22}{7}\times 98\] \[\therefore \]Number of revolutions \[=\frac{1540\times 100}{308}=500\]


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