A) 6 years
B) 4 years
C) 8 years
D) 5 years
Correct Answer: B
Solution :
Let the principal be Rs. 1. \[\therefore \]\[A=P{{\left( 1+\frac{R}{100} \right)}^{T}}\] \[\Rightarrow \]\[8=1{{\left( 1+\frac{R}{100} \right)}^{3}}\Rightarrow {{2}^{3}}={{\left( 1+\frac{R}{100} \right)}^{3}}\] \[\Rightarrow \] \[={{\left( 1+\frac{r}{100} \right)}^{3}}={{2}^{4}}={{\left( 1+\frac{r}{100} \right)}^{4}}\] \[\therefore \]Time\[=4\]yearsYou need to login to perform this action.
You will be redirected in
3 sec