A) \[\frac{2(x+4)}{x+3}\]
B) \[\frac{x+3}{2(x+4)}\]
C) \[\frac{x+4}{x+3}\]
D) \[\frac{x+3}{x+4}\]
Correct Answer: A
Solution :
\[\frac{{{x}^{2}}-x-6}{{{x}^{2}}-9}+\frac{{{x}^{2}}+2x-24}{{{x}^{2}}-x-12}\] \[=\frac{(x-3)(x+2)}{(x-3)(x+3)}+\frac{(x+6)(x-4)}{(x-4)(x+3)}\] \[=\frac{x+2}{x+3}+\frac{(x+6)}{x+3}=\frac{(x+2)+(x+6)}{x+3}\] \[=\frac{2x+8}{x+3}=\frac{2(x+4)}{x+3}\]You need to login to perform this action.
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