2. Sample Papers
  3. SSC

SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-4

  • question_answer
    In the given figure if\[EC||AB\], \[\angle ECD={{70}^{o}}\],\[\angle BDO={{20}^{o}}\] then \[\angle OBD\] is equal to

    A) \[{{70}^{o}}\]                        

    B) \[{{60}^{o}}\]

    C) \[{{50}^{o}}\]              

    D)        \[{{20}^{o}}\]

    Correct Answer: C

    Solution :

    \[\angle AOD=\angle ECO\Rightarrow \angle AO={{70}^{o}}\] So\[\angle BOD={{110}^{o}}\] Hence in\[\Delta BOD\] \[\angle OBD+\angle BOD+\angle ODB={{180}^{o}}\] \[\angle OBD={{180}^{o}}-({{110}^{o}}+{{20}^{o}})\] \[\angle OBD={{50}^{o}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner