A) \[{{90}^{o}}-\frac{1}{2}\angle A\]
B) \[{{90}^{o}}+\angle A\]
C) \[{{90}^{o}}+\frac{1}{2}\angle A\]
D) \[{{180}^{o}}-\frac{1}{2}\angle A\]
Correct Answer: C
Solution :
In\[\Delta BOC\], \[\angle 1+\angle 2+\angle BOC={{180}^{o}}\] \[\angle A+\angle B+\angle C={{180}^{o}}\]You need to login to perform this action.
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