A) 31 cm
B) 62 cm
C) 124 cm
D) 961 cm
Correct Answer: C
Solution :
Sides of the squares are\[6\,\,cm\], \[6\,\,cm,\]\[8\,\,cm,\] \[10\,\,cm,\]\[19\,\,cm\]and\[20\,\,cm\]respectively. Sum of their areas\[=({{6}^{2}}+{{8}^{2}}+{{10}^{2}}+{{19}^{2}}+{{20}^{2}})\]\[c{{m}^{2}}\] \[=(36+64+100+361+400)\,\,c{{m}^{2}}\] \[=961\,\,c{{m}^{2}}\] \[\therefore \]Area of largest other square\[=961\,\,c{{m}^{2}}\] \[\therefore \]Its side\[=\sqrt{961}=31\,\,cm\] \[\therefore \]Required perimeter \[=4\times 31=124\,\,cm\]
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