SSC
Sample Paper
SSC CHSL (10+2) Sample Test Paper-4
question_answer
\[ACB\] is a tangent to a circle at\[C\]. \[CD\] and \[CE\] are chords such that \[\angle ACE>\angle ACD\]. If\[\angle ACD=\angle BCE={{50}^{o}}\], then:
A) \[CD=DE\]
B) \[ED\] is not parallel to\[AB\]
C) ED passes through the centre of the circle
D) a CDE is a right angled triangle
Correct Answer:
A
Solution :
Join\[ED\], then \[\angle DEC=\angle ACD={{50}^{o}}\] (angles in alternate segment) \[\angle EDC=\angle BCE={{50}^{o}}\] (cyclic in alternate segment) \[\therefore \] \[\angle DEC=\angle EDC\] So, \[CD=CE\]