SSC
Sample Paper
SSC CHSL (10+2) Sample Test Paper-5
question_answer
Through each vertex of a triangle, a line parallel to the opposite side is drawn. The ratio of the perimeter of the new triangle, thus formed, with that of the original triangle is
A)\[3:2\]
B)\[4:1\]
C)\[2:1\]
D) \[2:3\]
Correct Answer:
C
Solution :
\[AQ||CB\], and\[AC||QB\] \[\therefore \]\[AQBC\], is a parallelogram \[\Rightarrow \] \[BC=AQ\] Again, \[AR||BC\] and\[AB||RC\] \[\therefore \]\[ARCB\]is a parallelogram. \[\Rightarrow \] \[BC=AR\Rightarrow AQ=AR\] \[\Rightarrow \] \[AQ=AR=\frac{1}{2}QR\] Similarly, \[AB=\frac{1}{2}PR\] and \[AC=\frac{1}{2}PQ\] \[\therefore \]Required ratio \[=(PQ+QR+RP):(AB+BC+CA)\] \[=2:1\]