A) \[(x+3)(x+1)\]
B) \[({{x}^{2}}-1)(x-2)(x+3)\]
C) \[(x-1)(x-2)(x-3)\]
D) \[({{x}^{2}}-1)(x+2)(x+3)\]
Correct Answer: B
Solution :
(i)\[{{x}^{2}}-1={{x}^{2}}-{{(1)}^{2}}\] \[=(x-1)(x+1)\] (ii)\[{{x}^{2}}+4x+3={{x}^{2}}+3x+x+3\] \[=x(x+3)(x+1)\] (iii) \[{{x}^{2}}-3x+2={{x}^{2}}-2x-x+2\] \[=x(x-2)-1(x-2)\] LCM\[=(x-1)(x+1)(x-2)(x+3)\]You need to login to perform this action.
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