A) \[\frac{\pi }{4}{{m}^{2}}\]
B) \[\frac{\pi }{2}{{m}^{2}}\]
C) \[\pi {{m}^{2}}\]
D) \[2\pi {{m}^{2}}\]
Correct Answer: B
Solution :
Side of square \[=\sqrt{2}\] metre Radius of in-circle \[=\frac{\sqrt{2}}{2}=\frac{1}{\sqrt{2}}\] metre Area of the circle \[=\pi {{r}^{2}}\] \[=\pi \times \frac{1}{2}=\frac{\pi }{2}\] sq. metre.
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