A) 4
B) 5
C) 10
D) 12
Correct Answer: C
Solution :
\[\frac{2p}{{{p}^{2}}-2p+1}=\frac{1}{4}\] \[\Rightarrow \]\[\frac{{{p}^{2}}-2p+1}{2p}=4\] \[\Rightarrow \]\[\frac{{{p}^{2}}-2p+1}{p}=8\] \[\Rightarrow \]\[\frac{{{p}^{2}}}{p}-\frac{2p}{p}+\frac{1}{p}=8\] \[\Rightarrow \] \[p+\frac{1}{p}=8+2=10\]You need to login to perform this action.
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