A) \[\frac{{{a}_{1}}}{{{a}_{2}}}\cancel{=}\frac{{{b}_{1}}}{{{b}_{2}}}\]
B) \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\cancel{=}\frac{{{c}_{1}}}{{{c}_{2}}}\]
C) \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{{{c}_{1}}}{{{c}_{2}}}\]
D) \[\frac{{{a}_{1}}}{{{a}_{2}}}\cancel{=}\frac{{{c}_{1}}}{{{c}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\]
Correct Answer: A
Solution :
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