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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-6

  • question_answer
    If \[\frac{2p}{{{p}^{2}}-2p+1}=\frac{1}{4}\]\[P\cancel{=}O,\] then the value of \[P+\frac{1}{P}\] is

    A)  4     

    B)                     5

    C)  10                   

    D)         12

    Correct Answer: C

    Solution :

     \[\frac{2p}{{{p}^{2}}-2p+1}=\frac{1}{4}\] \[\Rightarrow \]\[\frac{{{p}^{2}}-2p+1}{2p}=4\] \[\Rightarrow \]\[\frac{{{p}^{2}}-2p+1}{p}=8\] \[\Rightarrow \]\[\frac{{{p}^{2}}}{p}-\frac{2p}{p}+\frac{1}{p}=8\] \[\Rightarrow \] \[p+\frac{1}{p}=8+2=10\]


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