A) 0
B) 1
C) 2
D) -1
Correct Answer: A
Solution :
\[\cos x+\cos y=2\] \[\because \]\[\cos x\le 1\] \[\Rightarrow \]\[\cos x=1:\cos y=1\] \[\Rightarrow \]\[x=y={{0}^{o}}\] \[\therefore \]\[\sin x+\sin y=0\]You need to login to perform this action.
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