2. Sample Papers
  3. SSC

SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-7

  • question_answer
    Delhi and Jaipur are 403 km apart. An express bus leaves Delhi for Jaipur at 5 am and runs at an average speed of 60 km/hr. Another deluxe bus leaves Jaipur for Delhi at the same time and runs at an average speed of 64 km/hr. Where will the two buses meet?

    A)  200 km from Delhi

    B)  200 km from Jaipur

    C)  195 km from Delhi

    D)  195 km from Jaipur

    Correct Answer: C

    Solution :

     If both the buses meet after \[x\] hours, then \[x\times 60+x\times 64=403\] \[\Rightarrow \] \[124\,\,x=403\] \[\Rightarrow \]\[x=\frac{403}{124}\] hours = 3.25 hours \[\therefore \]Required distance from Delhi \[=60\times 3.25=195~\]km


You need to login to perform this action.
You will be redirected in 3 sec spinner