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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-7

  • question_answer
    If p= 102 then the value of \[p\left( p2-6p+12 \right)\]is

    A)  1000008                      

    B)  10000008

    C)  999992                        

    D)  9999992

    Correct Answer: A

    Solution :

     Given. p=102 \[\therefore \] \[p({{p}^{2}}-6p+12)\] \[={{p}^{3}}-6{{p}^{2}}+12p\] \[={{(p)}^{3}}-3.{{p}^{2}}.2+3.p.{{(2)}^{2}}-{{2}^{3}}+8\] \[={{(p-2)}^{3}}+8={{(102-2)}^{3}}+8\] \[={{(100)}^{3}}+8=1000008\]


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