A) \[10\frac{2}{3}\] days
B) \[10\frac{5}{6}\] days
C) \[11\frac{3}{4}\] days
D) \[11\frac{2}{7}\]days
Correct Answer: B
Solution :
Work done by Kamal and Debashish in first two days \[=\frac{1}{20}+\frac{1}{10}=\frac{5+6}{60}=\frac{11}{60}\] Work done in first 10 days \[=\frac{55}{60}=\frac{11}{12}\] Remaining work \[=1-\frac{11}{12}=\frac{1}{12}\] \[\therefore \] Time taken by Debashish \[=\frac{1}{12}\times 10=\frac{5}{6}\] day \[\therefore \]Total time \[=10+\frac{5}{6}\] \[=10\frac{5}{6}\] daysYou need to login to perform this action.
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