A) 1000008
B) 10000008
C) 999992
D) 9999992
Correct Answer: A
Solution :
Given. p=102 \[\therefore \] \[p({{p}^{2}}-6p+12)\] \[={{p}^{3}}-6{{p}^{2}}+12p\] \[={{(p)}^{3}}-3.{{p}^{2}}.2+3.p.{{(2)}^{2}}-{{2}^{3}}+8\] \[={{(p-2)}^{3}}+8={{(102-2)}^{3}}+8\] \[={{(100)}^{3}}+8=1000008\]You need to login to perform this action.
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