A) \[\frac{5}{12}\]
B) \[\frac{12}{5}\]
C) 5
D) 12
Correct Answer: B
Solution :
\[A{{B}^{2}}=A{{C}^{2}}+B{{C}^{2}}=9+16=25\] \[\therefore \] \[AB=\sqrt{25}=5\] Area of \[\Delta \,ABC~=\frac{1}{2}\times AB\times CD\] \[\Rightarrow \]\[\frac{1}{2}\times 4\times 3=\frac{1}{2}\times 5\times CD\] \[\Rightarrow \] \[CD=\frac{12}{5}\]You need to login to perform this action.
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