A) 422.4
B) 690.0
C) 537.6
D) 960.0
Correct Answer: D
Solution :
Area of quadrilateral ABCD = Area of \[\Delta \]ABD + Area of \[\Delta \]BCD \[=\frac{1}{2}\times BD\times AL+\frac{1}{2}\times BD\times CM\] \[=\frac{1}{2}\times BD(AL+CM)\] \[=\frac{1}{2}\times 64(13.2+16.8)\] \[=\frac{1}{2}\times 64\times 30=960\] sq. cmYou need to login to perform this action.
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