A) \[\frac{10}{\sqrt{3}}\] m
B) \[\frac{20}{\sqrt{3}}\]m
C) \[10\sqrt{3}\]m
D) \[20\sqrt{3}\]m
Correct Answer: C
Solution :
AB = wall =10 metre \[\angle \]ACB = \[30{}^\circ \] BC=\[x\] metre \[\therefore \] From \[\Delta \]ABC, tan \[30{}^\circ \]=\[\frac{AB}{BC}\] \[\Rightarrow \] \[\frac{1}{\sqrt{3}}=\frac{10}{x}\] \[\Rightarrow \]\[x=10\sqrt{3}\] metreYou need to login to perform this action.
You will be redirected in
3 sec