A) \[\frac{{{c}^{2}}}{ab}\]
B) \[\frac{{{a}^{2}}+{{c}^{2}}}{b}\]
C) \[\frac{{{b}^{2}}}{ac}\]
D) \[\frac{{{a}^{2}}}{bc}\]
Correct Answer: D
Solution :
\[\tan \,B\,=\frac{AC}{AB}=\frac{b}{c}\] \[\tan \,C\,=\frac{AB}{AC}=\frac{c}{b}\] \[\therefore \] \[\tan \,B\,+\tan \,C=\frac{b}{c}+\frac{c}{b}\] \[=\frac{{{b}^{2}}+{{c}^{2}}}{bc}=\frac{{{a}^{2}}}{bc}\]You need to login to perform this action.
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