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SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-8

  • question_answer
    If \[a+b=5,{{a}^{2}}+{{b}^{2}}=13,\] The value of \[a-b\](where a > b) is

    A)  1                                

    B)  \[-\text{ }2\]

    C)  2                                

    D)  \[-\text{ }1\]

    Correct Answer: A

    Solution :

     \[{{(a+b)}^{2}}={{a}^{2}}+{{b}^{2}}+2ab\] \[\Rightarrow \]\[25=13+2ab\] \[\Rightarrow \]\[2ab=25-13=12\] \[\therefore \] \[{{\left( a-b \right)}^{2}}=\text{ }{{a}^{2}}+{{b}^{2}}-2ab\] \[=13-12=1\] \[\Rightarrow \]\[a-b=1\]


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