A) 4
B) 5
C) 2
D) 3
Correct Answer: A
Solution :
\[A=P{{\left( 1+\frac{R}{100} \right)}^{T}}\] \[\Rightarrow \]279841 \[=160000{{\left( 1+\frac{15}{100} \right)}^{T}}\] \[\Rightarrow \]\[\frac{279841}{160000}={{\left( \frac{23}{20} \right)}^{T}}\] \[\Rightarrow \]\[{{\left( \frac{23}{20} \right)}^{4}}={{\left( \frac{23}{20} \right)}^{T}}\] \[\Rightarrow \]T=4 yearsYou need to login to perform this action.
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