A) 5
B) 10
C) 15
D) 3
Correct Answer: A
Solution :
\[\frac{5x-3}{x}+\frac{5y-3}{y}+\frac{5z-3}{z}=0\] \[\Rightarrow \]\[\frac{5x}{x}-\frac{3}{x}+\frac{5y}{y}-\frac{3}{y}+\frac{5z}{z}-\frac{3}{z}=0\] \[\Rightarrow \]\[\frac{3}{x}+\frac{3}{y}+\frac{3}{z}=15\] \[\Rightarrow \]\[\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=\frac{15}{3}=5\]You need to login to perform this action.
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